A Simple Way to Solve Any Quadratic Equation

I stumbled across this last December but had no time
to investigate it until now. The technique is from Po-Shen Loh of the Department
of Mathematical Sciences, Carnegie Mellon University. Relevant articles:

· Math
Genius Has Come Up with a Wildly Simple New Way to Solve Quadratic Equations
(a bit of hyperbole, but what can you expect from the website sciencealert.com?)

· A
Different Way to Solve Quadratic Equations

· A
Simple Proof of the Quadratic Formula

· Quadratic Method:
Detailed Explanation

· Quadratic Method: Related
Work

In Elementary and Intermediate Algebra classes we spend a huge amount of time on the
factoring of polynomials, particularly second-degree polynomials with integer coefficients, as a way of
solving certain quadratic equations; i.e., those with rational number solutions. Of
course, in practical applications, the coefficients are not integers and the solutions are almost never rational numbers. So,
we then talk about radicals and complex numbers, completing the square and
eventually work our way up to the quadratic formula as the ultimate way to
solve any quadratic equation. What Po-Shen has described is a single technique
that can be taught at the beginning when the solutions are rational numbers, but will
still work on quadratic equations with real number and even complex number
solutions. In the above articles, he shows (including several videos) how to
justify and teach the technique right after the student has learned how to multiply
two binomials and has been introduced to the idea of a quadratic equation.

The basic idea in practice for solving any quadratic
equation of the form *Ax*^{2} + *Bx* + *C* = 0 is:

1. Take
the quadratic equation and put it in the form *x*^{2} + *Bx*
+ *C* = 0.

2. Let *r* = (-*B*/2 - *u*) and *s* = (-*B*/2 + *u*) where *u* is any
complex number. [note that *r* + *s* = – *B*]

3. Now
note that *r* x *s* = *B*^2/4 - *u*^2. Set *B*^2/4 - *u*^2 = *C* and solve for *u*. *r* and *s* are the
solutions to the original quadratic equation.

Note that in addition to solving any quadratic
equation, the technique also obviously leads to the factorization of the
second-degree polynomial: *P*(*x*) = (*x* – *r*)(*x* –
*s*).